PAT 乙级 1102

依旧简单的一集。#includebits/stdc.h using namespace std; int main() { int n, price, num, sumprice; string s, s1, s2; cin n; int max1 -1, max2 -1; for(int i 0; i n; i ) { cin s price num; sumprice price * num; if(num max1) s1 s; if(sumprice max2) s2 s; max1 max(num, max1); max2 max(sumprice, max2); } cout s1 max1 endl; cout s2 max2; return 0; }